Cracking the New York City SHSAT (Specialized High Schools Admissions Test) by Princeton Review

Author:Princeton Review
Language: eng
Format: epub
Publisher: Random House Children's Books
Published: 2018-06-26T04:00:00+00:00

Explanations:

1. C Use PEMDAS. The absolute value signs serve as parentheses, so first evaluate each of those. In |2 – 3 × 4|, first multiply to get |2 – 12|. Then, subtract to get |–10|. To get the absolute value of –10, drop the negative to get |–10| = 10. Now evaluate |8 ÷ 2 – 3|. First divide to get |4 – 3|. Then, subtract to get |1|. Then take the absolute value of 1 to get |1| = 1. Therefore, |2 – 3 × 4| – |8 ÷ 2 – 3| = 10 – 1 = 9, which is (C).

2. 3 To find the distance between two points on a number line, take the absolute value of the difference. Therefore, the distance between –5 and –2 is |–5 – (–2)| = |–5 + 2| = |–3| = 3. Therefore, the answer is 3.

3. F Initially, the account has a balance of –$52, which indicates a debt of $52. Denise deposits $36 into the account. Since a deposit adds money into an account, add $36 to –$52 to get –$52 + $36 = –$16. There is still a negative balance, so this is a debt of $16, which is (F).

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